In some cases you're tuning (or detuning) the antenna capacitively.
On other cases, like if your tv gets interference when you're standing in part the room, there may be standing waves causing interference, as the rf is bouncing around your room.
Depends. If the antennas were resonant dipoles placed some fraction of a wavelength away from each other (1/4 wave away), you may get some cancellation of the signal.
Look up the "yagi uda" antenna, it's the classic rooftop tv antenna. The elements are spaced by fractions of a wavelength to achieve directivity. One single element is driven, the others are just resonant lengths of wire.
as the distance increases the capacitance reduces. But C=Q/V doesn't mean you're not inducing any potential into the antenna... You're adding to the load... C=ε*A/d is the equation that says capacitance will decrease with distance, but that isn't going to induce any voltage in this case.
yes this is what I'm saying.
in the very near field, conductive tissue, ie a body, will have Eddy currents. Your body has an ε term as well as σ. You can definitely load an antenna. The R term will dominate but there will be some effect on inductance.
xkcd #2948: Electric vs Gas ( xkcd.com )
Alt text:...
If two identical radios are side by side and tuned to the same frequency, will they both pick up the signal at 100%, or will they wrestle for the same radio waves?
Gen Z is prioritizing living over working because they've seen 'the legacy of broken promises' in corporate America, a future-of-work expert says ( www.businessinsider.com )
A future-of-work expert said Gen Zers didn't have the "promise of stability" at work, so they're putting their personal lives and well-being first.
xkcd #217: e to the pi Minus pi (31 Jan 2007) ( programming.dev )
cross-posted from: programming.dev/post/8653164...